Is possible to recover the SS58 `u16` prefix from bytes `[u8; 2]`?

Question

I want to convert the [u8; 2] back to u16.

I found this isn't simply a u16::from_be_bytes or u16::from_le_bytes.

Answer 1

https://github.com/paritytech/substrate/blob/c4d36065764ee23aeb3ccd181c4b6ecea8d2447a/primitives/core/src/crypto.rs#L315-L336

It's impossible.

The information was lost in this algorithm.